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Nov 30, 2017 · 1 1/1+x is the Taylor's series solved by Newton Expansion 1/1+x = 1 - x + x^2 - x^3..... As x is a small number higher powers can be neglected and the equation reduces to 1-x.

Jul 7, 2017 · I'm not sure what you mean by "Feynman knew how to correct for the small errors in his approximation." Can you give more details / a reference?

I saw this in a proof for the Central Limit Theorem: $\ln (1-x) \approx -x$ when $x$ is small It seems to be true when I plug in small values of $x$. But why does it ...

Is there a method to mentally evaluate $e^{-x}$ for $x>0$? Just to have an idea when computing probabilities or anything that is an exponential function of some ...

Oct 27, 2018 · Since $\log 1/x=-\log x$, an approximation for very small $x$ would be the same as an approximation for very large $x$.

Jan 19, 2015 · Showing y≈x for small x if y=log (x+1) Ask Question Asked 10 years, 10 months ago Modified 10 years, 10 months ago

I would guess this is only an approximation, using a linear approximation of $e^x$ near $0$ of $e^x \approx 1 + x$ (the first two terms of the Taylor series).

Jan 24, 2015 · 5 How can I show with linear approximation that $y \approx x$ for small x? I know the rule $$f (x) \approx f (a) + f^ {\prime} (a) (x-a),$$ but I don't know how to put it to use in this …

Feb 9, 2014 · In physics, particularly in waves, we make use of the fact that for small angles (less than $\\pi/12$-ish), the sine function value of an angle is pretty close to the value of the angle …