Oct 19, 2016 · I want to read a number from stdin. I don't understand why scanf requires the use of & before the name of my variable: int i; scanf("%d", &i); Why does scanf need the address …

The & in C is an operator that returns the address of the operand. Think of it this way, if you would simply give scanf the variable a without the &, it will be passed to it by-value, which means scanf will …

Nov 24, 2012 · scanf(" %c", &c); The blank in the format string tells scanf to skip leading whitespace, and the first non-whitespace character will be read with the %c conversion specifier.

10 From scanf: On success, the function returns the number of items successfully read. This count can match the expected number of readings or fewer, even zero, if a matching failure happens. In the …

When the scanf() function completes, the input is pointing at the next newline character. The body of the loop reads and prints that character, so that when the loop restarts, the input is looking at the start of …

So snprintf writes some data to a string buffer, and sscanf reads from that created string. Where exactly does this replace scanf in that it reads from stdin?

You are reading input using scanf, and it is leaving the user's newline on the input stream, and that stray newline is wrongly getting read by a later call to scanf("%c").

The scanf() function skips leading whitespace automatically before trying to parse conversions other than characters. The character formats (primarily %c; also scan sets %[…] — and %n) are the …

Jan 30, 2016 · char str[25]; And you cannot use scanf to read sentences--it stops reading at the first whitespace, so use fgets to read the sentence instead. And in your last printf, you need the %c …

May 22, 2013 · I have to create and call a function from main. Then I have to call scanf to read two integers and print out the bigger one. Then I have to do another scanf, but this time with doubles …