Why does \\leq show up as \\le? - TeX - LaTeX Stack Exchange
When I type \leq, it shows up as if I had typed \le. How do I do the actual less-than-equals (>=) sign? Edit: I typed \leq and the output symbol was >, but I want >=. I am also using the site …
math mode - Is there a difference between \ge and \geq (or ... - TeX
Is there a difference between \ge and \geq (or equivalentely between \le and leq)? Ask Question Asked 13 years, 8 months ago Modified 13 years, 8 months ago
\\leq, \\le, \\leqslant and LuaLaTeX - LaTeX Stack Exchange
Jun 24, 2023 · I have a problem replacing \leq by \leqslant with LuaLaTeX (I didn't have this problem with PdfLaTeX). Here is an MWE: \documentclass [10pt,a4paper,french] {article} …
Is \leqq or \leq preferred over ≦? - LaTeX Stack Exchange
May 22, 2020 · Compared to ≤ / ≦ the macro versions \leq / \leqq are (probably) easier to type for most people and require only US-ASCII characters (which is most likely the reason why older …
\\ge and \\geq vs \\geqslant (and similarly with \\le, \\leq, and ...
Apr 1, 2020 · The symbols \leq (\le) and \leqslant have exactly the same meaning; similarly for \geq (\ge) and \geqslant. The preference for one or the other is basically subjective, but this is …
notation - $\leq$ V.S. $\leqslant$ - Mathematics Stack Exchange
May 15, 2015 · Is there a substantial difference between $\\leq$ and $\\leqslant$? My textbook uses both, but I could not tell why the authors selected one or the other. I asked my teacher, …
symbols - \lessim slanted variation - TeX - LaTeX Stack Exchange
Mar 19, 2017 · I need a \leq symbol underlined like the symbol \leqslant (in order to obtain a sort of \lessim version of \leqslant) That is, with the \sim parallel to the bottom part of \leq (and as …
Variant of $\leq$ (less or equal)-symbol - LaTeX Stack Exchange
Jul 17, 2015 · I am looking for a way to include a \\leq that (to me) is less ugly. In the font I am using \\leq simply produces a < with an underline, but in my handwriting the lower "arm" of …
Clarification on proof that $\\liminf a_n \\leq \\limsup a_n$
Feb 21, 2025 · The proof argues that because $\alpha \leq \beta$ for all choices of $\alpha$ and $\beta$, we must have $\liminf x_n \leq \limsup x_n$. However, how do we rigorously rule out …
using less than or equal to symbol - TeX - LaTeX Stack Exchange
The code compiles without any error but where I should be getting a less than or equal to sign I instead get the letters leq. I have also tried using the code \le .