I'm taking a course in computer architecture in which the main reference is the Computer Organization and Design by Patterson and Hennessy. I came across an example which I …

I am trying to answer this question: Consider a computer with a byte-addressable memory. A 40-bit memory address is divided as follows for cache processing. First, the 8 low-order bits are …

(For a) & b), my take is $2^ {16}$ of whatever are addressable units - the bus size not being an indication (see e.g. Intel 8086↔8088). It does not read 16 address lines/signals, nor does it …

1 Well, my question - if word addressable memory has more bytes than byte addressable memory - is derived from the fact that in word addressable memory each address addresses a word …

0 I am going over some practice questions for the Major field exam and it asks: A processor with a word-addressable memory has a two-way set-associative cache. A cache line is one word, so …

Consider a 32-bit microprocessor composed of 2 fields: the first byte contains the opcode and remainder an immediate operand or an operand address. What is the maximum directly …

For example, if the address lines are enough for 64GB, and other hardware requires 2GB addressable space, then depending on the hardware, only 32GB, or 48GB, or 56GB RAM …

I am confused on byte addressable/word addressable architecture. I have studied MIPS implementation and I came to know that when the data is retrieved from main memory, it is …

Jun 27, 2019 · In a byte addressable system those are bytes (ie, octets of 8 bits); you can also have a word-addressable system where you can only address groups of, say, 32 bits. In a …

Aug 23, 2020 · Assume the memory is 4-byte addressable. MY QUESTION IS: what is the difference between an "address" and "the memory is 4 byte addressable"? I understand an …